(3x-2)^(1/2)=7

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Solution for (3x-2)^(1/2)=7 equation:


D( x )

3*x-2 < 0

3*x-2 < 0

3*x-2 < 0

3*x-2 < 0 // + 2

3*x < 2 // : 3

x < 2/3

x in <2/3:+oo)

(3*x-2)^(1/2) = 7 // - 7

(3*x-2)^(1/2)-7 = 0

(3*x-2)^(1/2) = -7 // + 7

(3*x-2)^(1/2) = 7 // ^ 2

abs(3*x-2) = 7^2 // - 7^2

abs(3*x-2)-7^2 = 0

x in (-oo:+oo)

abs(3*x-2)

3*x-2 >= 0

3*x-2 >= 0 // + 2

3*x >= 2 // : 3

x >= 2/3

x in <2/3:+oo)

3*x-7^2-2 = 0

x in (-oo:2/3)

2-(3*x)-7^2 = 0

abs(3*x-2)-7^2 = 0

/ | 2-(3*x)-7^2 = 0 i x in (-oo:2/3) | 3*x-7^2-2 = 0 i x in <2/3:+oo)

x in (-oo:2/3)

2-(3*x)-7^2 = 0

-3*x-47 = 0 // + 47

-3*x = 47 // : -3

x = 47/(-3)

x = -47/3

x in <2/3:+oo)

3*x-7^2-2 = 0

3*x-51 = 0 // + 51

3*x = 51 // : 3

x = 51/3

x = 17

x in { -47/3}

x = 17

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